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16n^2-24022n+9000000=0
a = 16; b = -24022; c = +9000000;
Δ = b2-4ac
Δ = -240222-4·16·9000000
Δ = 1056484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1056484}=\sqrt{4*264121}=\sqrt{4}*\sqrt{264121}=2\sqrt{264121}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24022)-2\sqrt{264121}}{2*16}=\frac{24022-2\sqrt{264121}}{32} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24022)+2\sqrt{264121}}{2*16}=\frac{24022+2\sqrt{264121}}{32} $
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